Friday

Why is the Product of the Reaction of an Alkene Halogenation an Anti-Addition Product



As a student of chemistry, you'll learn many reaction mechanisms. Molecules follow different patterns of graded reactivity depending on the type of reaction can take place. Halogenation olefin is a reaction in which a carbon double bond attacks a neutral molecule halogen and wind up form a vicinal dihalides. The two halogen atoms adds faces opposite the pi-bond, this is the reason why this reaction is considered an anti addition.

The response begins when the nucleophile pi bond for a molecule of bromine. Halogens are very more electronegative and dislike attacked. If the atom Bromine is attacked, it is taking revenge or attack immediately with one of the 3 pairs of electrons.

This translates the bromine, bound to two carbon atoms, Atom very atoms that a pi between them link. The second molecule of bromine grabs electrons that used to bind the bromine atoms and breaks away in solution in the form of a negative Nucleophilic halide.

The crucial intermediary

The halogen Atom who was attacked and attacked, is now linked to two carbon atoms form a ring 3-atom. This is called a bromonium because Bromine has a positive charge.

If this reaction took place with the bridge chlorine resulting would be called a Chloronium bridge.

To compensate for these costs, bromine pulling electrons by carbon. The attached carbon atoms are therefore partly positive and subtracts the second negative Bromine solution.

Bromine solution approaches the molecule with the intended attack on one of two partially positive carbon atoms. The bromonium-bridge is perched on the molecule, with its carbon bonds are preventing the advance of a nucleophile in solution.

This requires offensive bromide ion to attack the face opposite of the molecule, away from the bridge and the associated steric hindrance bromonium.